Need help with acceleration/time physics...
Post: #17
It's because you are relating the area under a curve on the velocity graph to the distance that makes it calculus. Calculus was developed partly to solve problems just like this.
Yes, finding the area of a rectangle and a triangle is easy, but would you have ever guessed that doing so relates the velocity to the distance? Unless you were told so, I'd suspect that you wouldn't have.
Yes, finding the area of a rectangle and a triangle is easy, but would you have ever guessed that doing so relates the velocity to the distance? Unless you were told so, I'd suspect that you wouldn't have.
Scott Lembcke - Howling Moon Software
Author of Chipmunk Physics - A fast and simple rigid body physics library in C.
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